Returns the Genero type name of a column in the result set produced by the SQL statement.


getResultType( index INTEGER )
  1. index is the ordinal position of the result set column (starts at 1).


Call the getResultType() method to query the type of a column in the result set, after executing the SQL statement with the open() method and fetching a row with fetch().

The method takes the position of the column as the parameter.

The type name is a string that represents a Genero type. For example, "INTEGER", "DECIMAL(10,2)", "DATE", "DATETIME YEAR TO SECOND".

For DATETIME types, when the second qualifier is a FRACTION with a precision of 3, the type name returned is "DATETIME … TO FRACTION" without precision.

The column type returned by the getResultType() method can differ, depending on the type of database server, the character set locale, and the length semantics used.

The native column type is provided by the database client software. This native type is then converted to a Genero type. For example, if you define a column with Oracle's native DATE type, the resulting type returned by getResultType() will be a Genero DATETIME YEAR TO SECOND, which corresponds to Oracle's DATE (YYYY-MM-DD hh:mm:ss).

Furthermore, depending on the character set and the length semantics used, the size of CHAR/VARCHAR types can differ, in order to get a Genero type that is large enough to hold the maximum character string the query may return. The resulting type can for example be different when using UTF-8 with CHAR or with BYTE length semantics. When using a single byte character set and BYTE length semantics, or when using UTF-8 and CHAR length semantics, the char size returned by getResultType() will always match the size of the database column in character units. For more details, see Length semantics settings.


DEFINE sh base.SqlHandle, i INT
FOR i=1 TO sh.getResultCount()
    DISPLAY sh.getResultType(i)

For a complete example, see Example 2: SqlHandle with result set SQL.