Example: upload a file in a multipart request

Shows an example of a method you might use from a client to upload an image along with other data in a function using a form-data type HTTP multipart request.

Example multipart request

In this sample REST function there is an example of a multipart request. The function has three input parameters:
  • "id" is defined as type INTEGER.
  • "img" is defined as type STRING with a WSAttachment attribute. The REST engine treats the parameter value as a path to a file to be attached. The WSMedia attribute handles the data format for images. The wildcard (image/*) in WSMedia allows for all image types. If the file can be any type, WSMedia is not specified with WSAttachment.
  • An input parameter "submit" is defined as type STRING.

The GWS stores the file in a temporary directory on the server, and returns the absolute path to the file in the input parameter ("img"). When the call to the function ends, the file will be removed unless it is saved to a location on disk.

The new_fname variable is set to create a path to the current directory, to which the filename is added with the os.Path.baseName instruction. The os.Path.rename instruction moves the file from the temporary directory to the current directory.

WSThrows – is set to handle errors. If the id is missing or there is a problem renaming and moving the file, the message field of the userError variable is set, and a call to SetRestError() returns the message defined in WSThrows for the error.


  message STRING

    id INTEGER,
    img STRING ATTRIBUTES(WSAttachment,WSMedia = "image/*"),
    submit STRING
              WSPath = "/files/fetch",
              WSDescription = "upload image file to the server from browser",
              WSThrows = "400:@userError")
    DEFINE ret, new_fname STRING
    IF id == 0 THEN
        LET userError.message = "Missing id"
        LET ret = SFMT("<HTML><body><h1>Must have an ID %1</h1></body></HTML>",id)
        CALL com.WebServiceEngine.SetRestError(400,userError)
            LET new_fname = os.Path.baseName(img)
            LET new_fname = os.Path.pwd()||"/"||new_fname
            LET ok = os.Path.rename(img,new_fname)
            LET ret = SFMT("Got image with ID %1",id)
            LET userError.message = "Error uploading file"
            LET ret = SFMT("Error uploading file %1",id)
            CALL com.WebServiceEngine.SetRestError(400,userError)  
        END TRY
    END IF
    RETURN ret

Create a client side HTML page to upload file

The "fetchFiles" function needs to be called by the client to upload a file. This example shows you how to create a simple HTML page to select the file to upload. The HTML page contains a form with two input fields and one submit button, according to the function's input parameters.
  1. In a text editor create the form from the code sample. Remember to change the action tag value to the URL of your server.
  2. Save the file to a .html file, for example, upload.html, and place it on the client side.
  3. Open the file locally in a browser and select a file to upload. Ensure the service is running.
<!DOCTYPE html>
   <form name = "Upload" method = "post" 
    action = "http://localhost:8090/Myservice/files/fetch" 
    enctype = "multipart/form-data">
        <label for = "name">ID:</label>
        <input type = "text" name = "id"/>
        <input type = "file" name = "img" accept = "image/png, image/jpeg" />
    <input type = "submit" name = "submit" value="Send"/>
Figure: Sample output of multipart HTTP request

In the output the image is sent in parts. Parts are separated by boundaries, the


string in the output example. These are combined into one or more sets of data in the body.

On successfully receiving the file, the server returns the message to display in the browser. Otherwise, an error is returned and displayed.

Sample output of multipart HTTP request