util.Integer.parseHexString

Returns an INTEGER from its hexadecimal (base 16) string representation.

Syntax

util.Integer.parseHexString(
  s STRING
 )
  RETURNS INTEGER
  1. s is the string in hexadecimal.

Usage

The util.Integer.parseHexString() method scans the hexadecimal string and converts it to an integer value.
Note:

The parseHexString() method is case-insensitive for A-F hexadecimal letters: The hexadecimal strings "ae3f", "aE3f" and "AE3F" are equivalent.

If the hexadecimal string does not fit in an INTEGER or if it contains an invalid hexadecimal representation, the method raises the numeric conversion error -1213, that can be trapped with a TRY/CATCH or WHENEVER ANY ERROR.

Note:
Bitwise methods provided by the util.Integer class are based on the INTEGER type. Consider the following facts when using these methods:
  1. The INTEGER type is a four-byte signed integer: If the bit at position 31 is set to 1, the corresponding INTEGER value will be negative. Thus, util.Integer.not(0) produces the INTEGER value -1 (11111111 11111111 11111111 11111111).
  2. The NULL value for the INTEGER type is represented internally with the value 0x80000000 (10000000 00000000 00000000 00000000). When NULL is used with the util.Integer bitwise methods, it will be interpreted as 0x80000000 instead of a null value. However, if the result of the bitwise operation produces the value 0x80000000, it will be interpreted as NULL when used in an expression.

Example

IMPORT util
MAIN
    DISPLAY util.Integer.parseHexString("6F12") -- displays 28434
END MAIN