util.Integer.setBit
Returns the INTEGER
parameter with the bit at the
designated position set to 1.
Syntax
util.Integer.setBit(
i INTEGER,
n INTEGER
)
RETURNS INTEGER
- i is the integer value to modify.
- n is the bit position (LSB is at position zero).
Usage
The util.Integer.setBit()
method modifies the integer value by setting the bit
at the position passed as second parameter.
Note: The position of the least significant bit (LSB) is the position zero:
- In
00000001
(integer 1), the bit set to 1 is at position 0. - In
00100010
(integer 34), the bits set to 1 are at position 1 and 5.
Note: Bitwise methods provided by the
util.Integer
class are
based on the INTEGER
type. Consider the following facts when using these methods: - The
INTEGER
type is a four-byte signed integer: If the bit at position 31 is set to 1, the correspondingINTEGER
value will be negative. Thus,util.Integer.not(0)
produces theINTEGER
value-1
(11111111 11111111 11111111 11111111
). - The
NULL
value for theINTEGER
type is represented internally with the value0x80000000
(10000000 00000000 00000000 00000000
). WhenNULL
is used with theutil.Integer
bitwise methods, it will be interpreted as0x80000000
instead of a null value. However, if the result of the bitwise operation produces the value0x80000000
, it will be interpreted asNULL
when used in an expression.
Example
IMPORT util
MAIN
DISPLAY util.Integer.setBit( 0, 0 ) -- displays 1 (00000001)
DISPLAY util.Integer.setBit( 1, 0 ) -- displays 1 (00000001)
DISPLAY util.Integer.setBit( 16, 2 ) -- displays 20 (00010100)
END MAIN