util.Integer.parseHexString
Returns an INTEGER
from its hexadecimal (base 16)
string representation.
Syntax
util.Integer.parseHexString(
s STRING
)
RETURNS INTEGER
- s is the string in hexadecimal.
Usage
The
util.Integer.parseHexString()
method scans the hexadecimal string and
converts it to an integer value.Note: Regarding A-F hexadecimal letters, the
parseHexString()
method is case-insensitive. The hexadecimal strings
"ae3f"
, "aE3f"
and "AE3F"
are
equivalent.If the hexadecimal string does not fit in an INTEGER
or if it contains an
invalid hexadecimal representation, the method raises the numeric conversion error -1213, that can
be trapped with a TRY/CATCH
or WHENEVER ANY ERROR
.
Note: Bitwise methods provided by the
util.Integer
class are
based on the INTEGER
type. Consider the following facts when using these methods: - The
INTEGER
type is a four-byte signed integer: If the bit at position 31 is set to 1, the correspondingINTEGER
value will be negative. Thus,util.Integer.not(0)
produces theINTEGER
value-1
(11111111 11111111 11111111 11111111
). - The
NULL
value for theINTEGER
type is represented internally with the value0x80000000
(10000000 00000000 00000000 00000000
). WhenNULL
is used with theutil.Integer
bitwise methods, it will be interpreted as0x80000000
instead of a null value. However, if the result of the bitwise operation produces the value0x80000000
, it will be interpreted asNULL
when used in an expression.
Example
IMPORT util
MAIN
DISPLAY util.Integer.parseHexString("6F12") -- displays 28434
END MAIN