util.Integer.parseBinaryString
Returns an INTEGER from its binary (base 2) string
representation
Syntax
util.Integer.parseBinaryString(
s STRING
)
RETURNS INTEGER
- s is the string in binary format (0 and 1).
Usage
The util.Integer.parseBinaryString() method scans the string as a set of 0 and 1
digits, and converts it to an integer value.
If the binary representation does not fit in an INTEGER or if it contains an
invalid binary representation, the method raises the numeric conversion error -1213, that can be
trapped with a TRY/CATCH or WHENEVER ANY ERROR.
Note: Bitwise methods provided by the
util.Integer class are
based on the INTEGER type. Consider the following facts when using these methods: - The
INTEGERtype is a four-byte signed integer: If the bit at position 31 is set to 1, the correspondingINTEGERvalue will be negative. Thus,util.Integer.not(0)produces theINTEGERvalue-1(11111111 11111111 11111111 11111111). - The
NULLvalue for theINTEGERtype is represented internally with the value0x80000000(10000000 00000000 00000000 00000000). WhenNULLis used with theutil.Integerbitwise methods, it will be interpreted as0x80000000instead of a null value. However, if the result of the bitwise operation produces the value0x80000000, it will be interpreted asNULLwhen used in an expression.
Example
IMPORT util
MAIN
DISPLAY util.Integer.parseBinaryString( "0010" ) -- displays 2
END MAIN