Example Counting the number of nodes in an XML document
This code example counts the number of nodes of each type.
IMPORT XML
DEFINE nbElt INTEGER
DEFINE nbAttr INTEGER
DEFINE nbComment INTEGER
DEFINE nbPI INTEGER
DEFINE nbTxt INTEGER
DEFINE nbCData INTEGER
MAIN
DEFINE document xml.DomDocument
DEFINE ind INTEGER
# Handle arguments
IF num_args() !=1 THEN
CALL ExitHelp()
END IF
# Create document, load it, and count the nodes
LET document = xml.DomDocument.Create()
CALL document.load(arg_val(1))
CALL CountDoc(document)
# Display result
DISPLAY "Results: "
DISPLAY " Elements: ",nbElt
DISPLAY " Attributes:",nbAttr
DISPLAY " Comments: ",nbComment
DISPLAY " PI: ",nbPI
DISPLAY " Texts: ",nbTxt
DISPLAY " CData: ",nbCData
END MAIN
FUNCTION CountDoc(d)
DEFINE d xml.DomDocument
DEFINE n xml.DomNode
LET n = d.getFirstDocumentNode()
WHILE (n IS NOT NULL )
CALL Count(n)
LET n = n.getNextSibling()
END WHILE
END FUNCTION
FUNCTION Count(n)
DEFINE n xml.DomNode
DEFINE child xml.DomNode
DEFINE next xml.DomNode
DEFINE node xml.DomNode
DEFINE ind INTEGER
DEFINE name STRING
IF n IS NOT NULL THEN
IF n.getNodeType() == "COMMENT_NODE" THEN
LET nbComment = nbComment + 1
END IF
IF n.getNodeType() == "ATTRIBUTE_NODE" THEN
LET nbAttr = nbAttr + 1
END IF
IF n.getNodeType() == "PROCESSING_INSTRUCTION_NODE " THEN
LET nbPI = nbPI + 1
END IF
IF n.getNodeType() == "ELEMENT_NODE" THEN
LET nbElt = nbElt + 1
END IF
IF n.getNodeType() == "TEXT_NODE" THEN
LET nbTxt = nbTxt +1
END IF
IF n.getNodeType() == "CDATA_SECTION_NODE" THEN
LET nbCData = nbCData + 1
END IF
IF n.hasChildNodes() THEN
LET name = n.getLocalName()
LET child = n.getFirstChild()
WHILE (child IS NOT NULL )
CALL Count(child)
LET child = child.getNextSibling()
END WHILE
END IF
IF n.hasAttributes() THEN
FOR ind = 1 TO n.getAttributesCount()
LET node = n.getAttributeNodeItem(ind)
CALL Count(node)
END FOR
END IF
END IF
END FUNCTION
FUNCTION ExitHelp()
DISPLAY "DomCount <xml>"
EXIT PROGRAM
END FUNCTION